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121221413101 is a prime number
BaseRepresentation
bin111000011100101011…
…0111111100011101101
3102120220010110211021201
41300321112333203231
53441230140204401
6131404403325501
711520660003355
oct1607126774355
9376803424251
10121221413101
1147456366938
121b5b0980891
13b57b268209
145c1d64bb65
153247320b01
hex1c395bf8ed

121221413101 has 2 divisors, whose sum is σ = 121221413102. Its totient is φ = 121221413100.

The previous prime is 121221413077. The next prime is 121221413147. The reversal of 121221413101 is 101314122121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94399490025 + 26821923076 = 307245^2 + 163774^2 .

It is an emirp because it is prime and its reverse (101314122121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121221413101 - 215 = 121221380333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121221413161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610706550 + 60610706551.

It is an arithmetic number, because the mean of its divisors is an integer number (60610706551).

Almost surely, 2121221413101 is an apocalyptic number.

It is an amenable number.

121221413101 is a deficient number, since it is larger than the sum of its proper divisors (1).

121221413101 is an equidigital number, since it uses as much as digits as its factorization.

121221413101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 121221413101 its reverse (101314122121), we get a palindrome (222535535222).

The spelling of 121221413101 in words is "one hundred twenty-one billion, two hundred twenty-one million, four hundred thirteen thousand, one hundred one".