Base | Representation |
---|---|
bin | 10001101000111110000… |
… | …000100011011110000011 |
3 | 11021212221202212211102121 |
4 | 101220332000203132003 |
5 | 124330112101011042 |
6 | 2324515305225111 |
7 | 153402653265535 |
oct | 21507600433603 |
9 | 4255852784377 |
10 | 1212221110147 |
11 | 42811123a023 |
12 | 176b2a492197 |
13 | 8a4094b8328 |
14 | 42959661855 |
15 | 217eca85367 |
hex | 11a3e023783 |
1212221110147 has 2 divisors, whose sum is σ = 1212221110148. Its totient is φ = 1212221110146.
The previous prime is 1212221110129. The next prime is 1212221110183. The reversal of 1212221110147 is 7410111222121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1212221110147 - 211 = 1212221108099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1212221110447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606110555073 + 606110555074.
It is an arithmetic number, because the mean of its divisors is an integer number (606110555074).
Almost surely, 21212221110147 is an apocalyptic number.
1212221110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212221110147 is an equidigital number, since it uses as much as digits as its factorization.
1212221110147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 1212221110147 its reverse (7410111222121), we get a palindrome (8622332332268).
The spelling of 1212221110147 in words is "one trillion, two hundred twelve billion, two hundred twenty-one million, one hundred ten thousand, one hundred forty-seven".
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