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121223021490803 is a prime number
BaseRepresentation
bin11011100100000001101111…
…001000100111001001110011
3120220012210210210111001100102
4123210001233020213021303
5111342104222000201203
61105453030503543015
734351034323265201
oct3344015710471163
9526183723431312
10121223021490803
1135697438399061
1211719a0075aa6b
13528438838968b
1421d1322c7c071
15e03450498888
hex6e406f227273

121223021490803 has 2 divisors, whose sum is σ = 121223021490804. Its totient is φ = 121223021490802.

The previous prime is 121223021490797. The next prime is 121223021490869. The reversal of 121223021490803 is 308094120322121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121223021490803 - 28 = 121223021490547 is a prime.

It is a super-2 number, since 2×1212230214908032 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121223021490203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60611510745401 + 60611510745402.

It is an arithmetic number, because the mean of its divisors is an integer number (60611510745402).

Almost surely, 2121223021490803 is an apocalyptic number.

121223021490803 is a deficient number, since it is larger than the sum of its proper divisors (1).

121223021490803 is an equidigital number, since it uses as much as digits as its factorization.

121223021490803 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 121223021490803 in words is "one hundred twenty-one trillion, two hundred twenty-three billion, twenty-one million, four hundred ninety thousand, eight hundred three".