Base | Representation |
---|---|
bin | 10110100101000101… |
… | …11111000110110111 |
3 | 1011021211021201200021 |
4 | 23102202333012313 |
5 | 144311303240320 |
6 | 5322515230011 |
7 | 606255013465 |
oct | 132242770667 |
9 | 34254251607 |
10 | 12122321335 |
11 | 5160809493 |
12 | 24238a8307 |
13 | 11b25c2207 |
14 | 82dd7d835 |
15 | 4ae383daa |
hex | 2d28bf1b7 |
12122321335 has 4 divisors (see below), whose sum is σ = 14546785608. Its totient is φ = 9697857064.
The previous prime is 12122321317. The next prime is 12122321339. The reversal of 12122321335 is 53312322121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53312322121 = 131 ⋅406964291.
It is a cyclic number.
It is not a de Polignac number, because 12122321335 - 25 = 12122321303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12122321339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1212232129 + ... + 1212232138.
It is an arithmetic number, because the mean of its divisors is an integer number (3636696402).
Almost surely, 212122321335 is an apocalyptic number.
12122321335 is a deficient number, since it is larger than the sum of its proper divisors (2424464273).
12122321335 is an equidigital number, since it uses as much as digits as its factorization.
12122321335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2424464272.
The product of its digits is 2160, while the sum is 25.
Adding to 12122321335 its reverse (53312322121), we get a palindrome (65434643456).
The spelling of 12122321335 in words is "twelve billion, one hundred twenty-two million, three hundred twenty-one thousand, three hundred thirty-five".
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