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12122401200000 = 27355713313581
BaseRepresentation
bin1011000001100111011101…
…1010101101011110000000
31120220220000222112022110020
42300121313122231132000
53042103134201400000
641440542040333440
72360546255030010
oct260316732553600
946826028468406
1012122401200000
1139540994a1033
12143949b774280
1369c1a31c2b50
142dca27bb7c40
151604e8ad7ba0
hexb06776ad780

12122401200000 has 1536 divisors, whose sum is σ = 51147686338560. Its totient is φ = 2474496000000.

The previous prime is 12122401199983. The next prime is 12122401200017. The reversal of 12122401200000 is 210422121.

12122401200000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (12122401199983) and next prime (12122401200017).

It is a super-2 number, since 2×121224012000002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 3385198210 + ... + 3385201790.

It is an arithmetic number, because the mean of its divisors is an integer number (33299274960).

Almost surely, 212122401200000 is an apocalyptic number.

12122401200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12122401200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25573843169280).

12122401200000 is an abundant number, since it is smaller than the sum of its proper divisors (39025285138560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12122401200000 is an equidigital number, since it uses as much as digits as its factorization.

12122401200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3674 (or 3642 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 12122401200000 its reverse (210422121), we get a palindrome (12122611622121).

The spelling of 12122401200000 in words is "twelve trillion, one hundred twenty-two billion, four hundred one million, two hundred thousand".