Base | Representation |
---|---|
bin | 111000011100111100… |
… | …0001011100111010000 |
3 | 102120220201211211121210 |
4 | 1300321320023213100 |
5 | 3441234402110412 |
6 | 131405314020120 |
7 | 11521123650234 |
oct | 1607170134720 |
9 | 376821754553 |
10 | 121230113232 |
11 | 47460269428 |
12 | 1b5b3877640 |
13 | b57ccc3217 |
14 | 5c208745c4 |
15 | 3247e8d83c |
hex | 1c39e0b9d0 |
121230113232 has 80 divisors (see below), whose sum is σ = 317522455040. Its totient is φ = 39853296000.
The previous prime is 121230113219. The next prime is 121230113233. The reversal of 121230113232 is 232311032121.
It is a junction number, because it is equal to n+sod(n) for n = 121230113199 and 121230113208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121230113233) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 947307 + ... + 1067637.
It is an arithmetic number, because the mean of its divisors is an integer number (3969030688).
Almost surely, 2121230113232 is an apocalyptic number.
121230113232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
121230113232 is an abundant number, since it is smaller than the sum of its proper divisors (196292341808).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121230113232 is a wasteful number, since it uses less digits than its factorization.
121230113232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120632 (or 120626 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 121230113232 its reverse (232311032121), we get a palindrome (353541145353).
The spelling of 121230113232 in words is "one hundred twenty-one billion, two hundred thirty million, one hundred thirteen thousand, two hundred thirty-two".
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