Base | Representation |
---|---|
bin | 10001101001000011100… |
… | …111001011011010101111 |
3 | 11021220012022210002112011 |
4 | 101221003213023122233 |
5 | 124330310132340302 |
6 | 2324532504222051 |
7 | 153405204335602 |
oct | 21510347133257 |
9 | 4256168702464 |
10 | 1212315121327 |
11 | 42815a310012 |
12 | 176b55a6a927 |
13 | 8a422b12c4b |
14 | 42967d34339 |
15 | 21805e555d7 |
hex | 11a439cb6af |
1212315121327 has 2 divisors, whose sum is σ = 1212315121328. Its totient is φ = 1212315121326.
The previous prime is 1212315121319. The next prime is 1212315121333. The reversal of 1212315121327 is 7231215132121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1212315121327 - 23 = 1212315121319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212315121357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606157560663 + 606157560664.
It is an arithmetic number, because the mean of its divisors is an integer number (606157560664).
Almost surely, 21212315121327 is an apocalyptic number.
1212315121327 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212315121327 is an equidigital number, since it uses as much as digits as its factorization.
1212315121327 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5040, while the sum is 31.
The spelling of 1212315121327 in words is "one trillion, two hundred twelve billion, three hundred fifteen million, one hundred twenty-one thousand, three hundred twenty-seven".
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