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121254983 is a prime number
BaseRepresentation
bin1110011101000…
…11010001000111
322110011101120022
413032203101013
5222020124413
620010525355
73001436033
oct716432107
9273141508
10121254983
1162499733
123473685b
131c176215
14121651c3
15a9a2608
hex73a3447

121254983 has 2 divisors, whose sum is σ = 121254984. Its totient is φ = 121254982.

The previous prime is 121254961. The next prime is 121254997. The reversal of 121254983 is 389452121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121254983 - 222 = 117060679 is a prime.

It is a Chen prime.

It is an alternating number because its digits alternate between odd and even.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121254923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60627491 + 60627492.

It is an arithmetic number, because the mean of its divisors is an integer number (60627492).

Almost surely, 2121254983 is an apocalyptic number.

121254983 is a deficient number, since it is larger than the sum of its proper divisors (1).

121254983 is an equidigital number, since it uses as much as digits as its factorization.

121254983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17280, while the sum is 35.

The square root of 121254983 is about 11011.5840368223. The cubic root of 121254983 is about 494.9559298248.

The spelling of 121254983 in words is "one hundred twenty-one million, two hundred fifty-four thousand, nine hundred eighty-three".