12125520154133 has 2 divisors, whose sum is σ = 12125520154134. Its totient is φ = 12125520154132.

The previous prime is 12125520154127. The next prime is 12125520154159. The reversal of 12125520154133 is 33145102552121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7970046058129 + 4155474096004 = 2823127^2 + 2038498^2 .

It is a cyclic number.

It is not a de Polignac number, because 12125520154133 - 2⁴ = 12125520154117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12125520154093 and 12125520154102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12125520954133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6062760077066 + 6062760077067.

It is an arithmetic number, because the mean of its divisors is an integer number (6062760077067).

Almost surely, 2^{12125520154133} is an apocalyptic number.

It is an amenable number.

12125520154133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12125520154133 is an equidigital number, since it uses as much as digits as its factorization.

12125520154133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36000, while the sum is 35.

The spelling of 12125520154133 in words is "twelve trillion, one hundred twenty-five billion, five hundred twenty million, one hundred fifty-four thousand, one hundred thirty-three".