12130001004119 has 2 divisors, whose sum is σ = 12130001004120. Its totient is φ = 12130001004118.

The previous prime is 12130001004091. The next prime is 12130001004133. The reversal of 12130001004119 is 91140010003121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12130001004119 - 2⁸ = 12130001003863 is a prime.

It is a super-2 number, since 2×12130001004119² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12130001004094 and 12130001004103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12130001004419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065000502059 + 6065000502060.

It is an arithmetic number, because the mean of its divisors is an integer number (6065000502060).

Almost surely, 2^{12130001004119} is an apocalyptic number.

12130001004119 is a deficient number, since it is larger than the sum of its proper divisors (1).

12130001004119 is an equidigital number, since it uses as much as digits as its factorization.

12130001004119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 12130001004119 in words is "twelve trillion, one hundred thirty billion, one million, four thousand, one hundred nineteen".