121300013133251 has 2 divisors, whose sum is σ = 121300013133252. Its totient is φ = 121300013133250.

The previous prime is 121300013133191. The next prime is 121300013133253. The reversal of 121300013133251 is 152331310003121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121300013133251 is a prime.

It is a super-2 number, since 2×121300013133251² (a number of 29 digits) contains 22 as substring.

Together with 121300013133253, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121300013133251.

It is not a weakly prime, because it can be changed into another prime (121300013133253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60650006566625 + 60650006566626.

It is an arithmetic number, because the mean of its divisors is an integer number (60650006566626).

Almost surely, 2^{121300013133251} is an apocalyptic number.

121300013133251 is a deficient number, since it is larger than the sum of its proper divisors (1).

121300013133251 is an equidigital number, since it uses as much as digits as its factorization.

121300013133251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 26.

Adding to 121300013133251 its reverse (152331310003121), we get a palindrome (273631323136372).

The spelling of 121300013133251 in words is "one hundred twenty-one trillion, three hundred billion, thirteen million, one hundred thirty-three thousand, two hundred fifty-one".