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1213001144320 = 211571011311279
BaseRepresentation
bin10001101001101100100…
…000001001100000000000
311021221222010122200011011
4101221230200021200000
5124333211243104240
62325124532130304
7153431204414620
oct21515440114000
94257863580134
101213001144320
11428481583269
12177107766994
138a501c9a504
14429d10b0880
15218462b66ea
hex11a6c809800

1213001144320 has 384 divisors, whose sum is σ = 3387499315200. Its totient is φ = 408305664000.

The previous prime is 1213001144309. The next prime is 1213001144323. The reversal of 1213001144320 is 234411003121.

It is a super-2 number, since 2×12130011443202 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213001144291 and 1213001144300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213001144323) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 948397441 + ... + 948398719.

It is an arithmetic number, because the mean of its divisors is an integer number (8821612800).

Almost surely, 21213001144320 is an apocalyptic number.

1213001144320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1213001144320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1693749657600).

1213001144320 is an abundant number, since it is smaller than the sum of its proper divisors (2174498170880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1213001144320 is a wasteful number, since it uses less digits than its factorization.

1213001144320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1545 (or 1525 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1213001144320 its reverse (234411003121), we get a palindrome (1447412147441).

The spelling of 1213001144320 in words is "one trillion, two hundred thirteen billion, one million, one hundred forty-four thousand, three hundred twenty".