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1213002019981 is a prime number
BaseRepresentation
bin10001101001101100100…
…011011111010010001101
311021221222012022011100001
4101221230203133102031
5124333212004114411
62325125003004301
7153431215022563
oct21515443372215
94257865264301
101213002019981
11428482021154
12177107b09691
138a502215c5b
14429d125ba33
15218463dadc1
hex11a6c8df48d

1213002019981 has 2 divisors, whose sum is σ = 1213002019982. Its totient is φ = 1213002019980.

The previous prime is 1213002019973. The next prime is 1213002020047. The reversal of 1213002019981 is 1899102003121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 876910509225 + 336091510756 = 936435^2 + 579734^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213002019981 - 23 = 1213002019973 is a prime.

It is a super-2 number, since 2×12130020199812 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1213002019981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213402019981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606501009990 + 606501009991.

It is an arithmetic number, because the mean of its divisors is an integer number (606501009991).

Almost surely, 21213002019981 is an apocalyptic number.

It is an amenable number.

1213002019981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213002019981 is an equidigital number, since it uses as much as digits as its factorization.

1213002019981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 37.

The spelling of 1213002019981 in words is "one trillion, two hundred thirteen billion, two million, nineteen thousand, nine hundred eighty-one".