1213003532537 has 2 divisors, whose sum is σ = 1213003532538. Its totient is φ = 1213003532536.

The previous prime is 1213003532423. The next prime is 1213003532539. The reversal of 1213003532537 is 7352353003121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1187186755561 + 25816776976 = 1089581^2 + 160676^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213003532537 - 2¹⁰ = 1213003531513 is a prime.

Together with 1213003532539, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1213003532497 and 1213003532506.

It is not a weakly prime, because it can be changed into another prime (1213003532539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606501766268 + 606501766269.

It is an arithmetic number, because the mean of its divisors is an integer number (606501766269).

Almost surely, 2^{1213003532537} is an apocalyptic number.

It is an amenable number.

1213003532537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213003532537 is an equidigital number, since it uses as much as digits as its factorization.

1213003532537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56700, while the sum is 35.

Adding to 1213003532537 its reverse (7352353003121), we get a palindrome (8565356535658).

The spelling of 1213003532537 in words is "one trillion, two hundred thirteen billion, three million, five hundred thirty-two thousand, five hundred thirty-seven".