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12130113438 = 2321374918943
BaseRepresentation
bin10110100110000001…
…01101011110011110
31011022100221121102200
423103000231132132
5144320302112223
65323354232330
7606411156132
oct132300553636
934270847380
1012130113438
115165150843
1224264256a6
1311b40bcb21
1483100b3c2
154aedc2a43
hex2d302d79e

12130113438 has 24 divisors (see below), whose sum is σ = 26473756608. Its totient is φ = 4013856672.

The previous prime is 12130113431. The next prime is 12130113439. The reversal of 12130113438 is 83431103121.

12130113438 is a `hidden beast` number, since 1 + 213 + 0 + 1 + 13 + 438 = 666.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12130113431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2457006 + ... + 2461937.

It is an arithmetic number, because the mean of its divisors is an integer number (1103073192).

Almost surely, 212130113438 is an apocalyptic number.

12130113438 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

12130113438 is an abundant number, since it is smaller than the sum of its proper divisors (14343643170).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12130113438 is a wasteful number, since it uses less digits than its factorization.

12130113438 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4919088 (or 4919085 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 12130113438 its reverse (83431103121), we get a palindrome (95561216559).

The spelling of 12130113438 in words is "twelve billion, one hundred thirty million, one hundred thirteen thousand, four hundred thirty-eight".

Divisors: 1 2 3 6 9 18 137 274 411 822 1233 2466 4918943 9837886 14756829 29513658 44270487 88540974 673895191 1347790382 2021685573 4043371146 6065056719 12130113438