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12130123442137 is a prime number
BaseRepresentation
bin1011000010000100001110…
…1100101110011111011001
31120221121222011021212012021
42300201003230232133121
53042214443100122022
641444300215014441
72361241524015331
oct260410354563731
946847864255167
1012130123442137
1139573a14a6928
12143aa9596a421
1369cb34024cac
142dd15b61c0c1
151607eba197c7
hexb0843b2e7d9

12130123442137 has 2 divisors, whose sum is σ = 12130123442138. Its totient is φ = 12130123442136.

The previous prime is 12130123442089. The next prime is 12130123442141. The reversal of 12130123442137 is 73124432103121.

12130123442137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11471199991056 + 658923451081 = 3386916^2 + 811741^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12130123442137 is a prime.

It is not a weakly prime, because it can be changed into another prime (12130123442537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065061721068 + 6065061721069.

It is an arithmetic number, because the mean of its divisors is an integer number (6065061721069).

Almost surely, 212130123442137 is an apocalyptic number.

It is an amenable number.

12130123442137 is a deficient number, since it is larger than the sum of its proper divisors (1).

12130123442137 is an equidigital number, since it uses as much as digits as its factorization.

12130123442137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 34.

Adding to 12130123442137 its reverse (73124432103121), we get a palindrome (85254555545258).

The spelling of 12130123442137 in words is "twelve trillion, one hundred thirty billion, one hundred twenty-three million, four hundred forty-two thousand, one hundred thirty-seven".