1213014434431 has 2 divisors, whose sum is σ = 1213014434432. Its totient is φ = 1213014434430.

The previous prime is 1213014434341. The next prime is 1213014434491. The reversal of 1213014434431 is 1344344103121.

Together with previous prime (1213014434341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1213014434431 - 2⁹ = 1213014433919 is a prime.

It is a super-2 number, since 2×1213014434431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213014434393 and 1213014434402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213014434491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606507217215 + 606507217216.

It is an arithmetic number, because the mean of its divisors is an integer number (606507217216).

Almost surely, 2^{1213014434431} is an apocalyptic number.

1213014434431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213014434431 is an equidigital number, since it uses as much as digits as its factorization.

1213014434431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1213014434431 its reverse (1344344103121), we get a palindrome (2557358537552).

The spelling of 1213014434431 in words is "one trillion, two hundred thirteen billion, fourteen million, four hundred thirty-four thousand, four hundred thirty-one".