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121302401039933 is a prime number
BaseRepresentation
bin11011100101001011101010…
…100001100011111000111101
3120220111101200220002221202112
4123211023222201203320331
5111344404304131234213
61105553315335103405
734356544402313141
oct3345135241437075
9526441626087675
10121302401039933
1135718072049223
1211731274811b65
13528b9c8ab51a9
1421d50d3469221
15e05549259ea8
hex6e52ea863e3d

121302401039933 has 2 divisors, whose sum is σ = 121302401039934. Its totient is φ = 121302401039932.

The previous prime is 121302401039929. The next prime is 121302401040091. The reversal of 121302401039933 is 339930104203121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77409695765284 + 43892705274649 = 8798278^2 + 6625157^2 .

It is a cyclic number.

It is not a de Polignac number, because 121302401039933 - 22 = 121302401039929 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121302401039923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60651200519966 + 60651200519967.

It is an arithmetic number, because the mean of its divisors is an integer number (60651200519967).

Almost surely, 2121302401039933 is an apocalyptic number.

It is an amenable number.

121302401039933 is a deficient number, since it is larger than the sum of its proper divisors (1).

121302401039933 is an equidigital number, since it uses as much as digits as its factorization.

121302401039933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 104976, while the sum is 41.

The spelling of 121302401039933 in words is "one hundred twenty-one trillion, three hundred two billion, four hundred one million, thirty-nine thousand, nine hundred thirty-three".