1213100131249 has 2 divisors, whose sum is σ = 1213100131250. Its totient is φ = 1213100131248.

The previous prime is 1213100131141. The next prime is 1213100131259. The reversal of 1213100131249 is 9421310013121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1212350740624 + 749390625 = 1101068^2 + 27375^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213100131249 - 2³¹ = 1210952647601 is a prime.

It is a super-2 number, since 2×1213100131249² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1213100131259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606550065624 + 606550065625.

It is an arithmetic number, because the mean of its divisors is an integer number (606550065625).

Almost surely, 2^{1213100131249} is an apocalyptic number.

It is an amenable number.

1213100131249 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213100131249 is an equidigital number, since it uses as much as digits as its factorization.

1213100131249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 1213100131249 in words is "one trillion, two hundred thirteen billion, one hundred million, one hundred thirty-one thousand, two hundred forty-nine".