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1213100131141 is a prime number
BaseRepresentation
bin10001101001110010011…
…001110000001101000101
311021222020000220201112201
4101221302121300031011
5124333412113144031
62325142425514501
7153433515660133
oct21516231601505
94258200821481
101213100131141
11428522442558
12177134942a31
138a519647ab2
1442a002ba753
152184ed1ad61
hex11a72670345

1213100131141 has 2 divisors, whose sum is σ = 1213100131142. Its totient is φ = 1213100131140.

The previous prime is 1213100131091. The next prime is 1213100131249. The reversal of 1213100131141 is 1411310013121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 960841050625 + 252259080516 = 980225^2 + 502254^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213100131141 - 27 = 1213100131013 is a prime.

It is a super-2 number, since 2×12131001311412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213100111141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606550065570 + 606550065571.

It is an arithmetic number, because the mean of its divisors is an integer number (606550065571).

Almost surely, 21213100131141 is an apocalyptic number.

It is an amenable number.

1213100131141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213100131141 is an equidigital number, since it uses as much as digits as its factorization.

1213100131141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1213100131141 its reverse (1411310013121), we get a palindrome (2624410144262).

The spelling of 1213100131141 in words is "one trillion, two hundred thirteen billion, one hundred million, one hundred thirty-one thousand, one hundred forty-one".