Base | Representation |
---|---|
bin | 10110100110001000… |
… | …00110001111101000 |
3 | 1011022102121201101012 |
4 | 23103010012033220 |
5 | 144321014020240 |
6 | 5323425243052 |
7 | 606421544534 |
oct | 132304061750 |
9 | 34272551335 |
10 | 12131001320 |
11 | 51656a7929 |
12 | 2426793488 |
13 | 11b4340cb9 |
14 | 83119cbc4 |
15 | 4aeeeab65 |
hex | 2d31063e8 |
12131001320 has 32 divisors (see below), whose sum is σ = 28481483520. Its totient is φ = 4641426240.
The previous prime is 12131001319. The next prime is 12131001329. The reversal of 12131001320 is 2310013121.
It is a super-2 number, since 2×121310013202 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12131001295 and 12131001304.
It is not an unprimeable number, because it can be changed into a prime (12131001329) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6592016 + ... + 6593855.
It is an arithmetic number, because the mean of its divisors is an integer number (890046360).
Almost surely, 212131001320 is an apocalyptic number.
12131001320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12131001320 is an abundant number, since it is smaller than the sum of its proper divisors (16350482200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12131001320 is a wasteful number, since it uses less digits than its factorization.
12131001320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13185905 (or 13185901 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 12131001320 its reverse (2310013121), we get a palindrome (14441014441).
The spelling of 12131001320 in words is "twelve billion, one hundred thirty-one million, one thousand, three hundred twenty".
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