Base | Representation |
---|---|
bin | 1011000010000111100101… |
… | …0101000111111000101111 |
3 | 1120221201021212101112101001 |
4 | 2300201321111013320233 |
5 | 3042223313421134432 |
6 | 41444525400301131 |
7 | 2361303031026205 |
oct | 260417125077057 |
9 | 46851255345331 |
10 | 12131023224367 |
11 | 395781339a603 |
12 | 143b0a71717a7 |
13 | 69cc48573508 |
14 | 2dd204d1d075 |
15 | 160850a019e7 |
hex | b0879547e2f |
12131023224367 has 2 divisors, whose sum is σ = 12131023224368. Its totient is φ = 12131023224366.
The previous prime is 12131023224323. The next prime is 12131023224413. The reversal of 12131023224367 is 76342232013121.
It is a weak prime.
It is an emirp because it is prime and its reverse (76342232013121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12131023224367 - 231 = 12128875740719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12131023224167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065511612183 + 6065511612184.
It is an arithmetic number, because the mean of its divisors is an integer number (6065511612184).
Almost surely, 212131023224367 is an apocalyptic number.
12131023224367 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131023224367 is an equidigital number, since it uses as much as digits as its factorization.
12131023224367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 37.
Adding to 12131023224367 its reverse (76342232013121), we get a palindrome (88473255237488).
The spelling of 12131023224367 in words is "twelve trillion, one hundred thirty-one billion, twenty-three million, two hundred twenty-four thousand, three hundred sixty-seven".
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