Base | Representation |
---|---|
bin | 1011000010000111101110… |
… | …1101100101101001100111 |
3 | 1120221201101122121002212221 |
4 | 2300201323231211221213 |
5 | 3042223404134122132 |
6 | 41444533345053211 |
7 | 2361304024531333 |
oct | 260417355455147 |
9 | 46851348532787 |
10 | 12131063192167 |
11 | 3957833a08a47 |
12 | 143b0b8627207 |
13 | 69cc539284ba |
14 | 2dd20a3647c3 |
15 | 160854298e97 |
hex | b087bb65a67 |
12131063192167 has 2 divisors, whose sum is σ = 12131063192168. Its totient is φ = 12131063192166.
The previous prime is 12131063192081. The next prime is 12131063192189. The reversal of 12131063192167 is 76129136013121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12131063192167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12131063192267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065531596083 + 6065531596084.
It is an arithmetic number, because the mean of its divisors is an integer number (6065531596084).
Almost surely, 212131063192167 is an apocalyptic number.
12131063192167 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131063192167 is an equidigital number, since it uses as much as digits as its factorization.
12131063192167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 43.
The spelling of 12131063192167 in words is "twelve trillion, one hundred thirty-one billion, sixty-three million, one hundred ninety-two thousand, one hundred sixty-seven".
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