1213111220117 has 2 divisors, whose sum is σ = 1213111220118. Its totient is φ = 1213111220116.

The previous prime is 1213111220063. The next prime is 1213111220131. The reversal of 1213111220117 is 7110221113121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 945890459761 + 267220760356 = 972569^2 + 516934^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213111220117 - 2¹⁰ = 1213111219093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1213111220092 and 1213111220101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213111220917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606555610058 + 606555610059.

It is an arithmetic number, because the mean of its divisors is an integer number (606555610059).

Almost surely, 2^{1213111220117} is an apocalyptic number.

It is an amenable number.

1213111220117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213111220117 is an equidigital number, since it uses as much as digits as its factorization.

1213111220117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 23.

Adding to 1213111220117 its reverse (7110221113121), we get a palindrome (8323332333238).

The spelling of 1213111220117 in words is "one trillion, two hundred thirteen billion, one hundred eleven million, two hundred twenty thousand, one hundred seventeen".