Base | Representation |
---|---|
bin | 10001101001110011000… |
… | …100011010001100010101 |
3 | 11021222020210221211102001 |
4 | 101221303010122030111 |
5 | 124333422444010143 |
6 | 2325143505315301 |
7 | 153434013011614 |
oct | 21516304321425 |
9 | 4258223854361 |
10 | 1213111313173 |
11 | 42852878a801 |
12 | 177138635b31 |
13 | 8a51ba61696 |
14 | 42a0198b87b |
15 | 21850cc914d |
hex | 11a7311a315 |
1213111313173 has 2 divisors, whose sum is σ = 1213111313174. Its totient is φ = 1213111313172.
The previous prime is 1213111313147. The next prime is 1213111313209. The reversal of 1213111313173 is 3713131113121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 890188476004 + 322922837169 = 943498^2 + 568263^2 .
It is an emirp because it is prime and its reverse (3713131113121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213111313173 - 29 = 1213111312661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213111713173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606555656586 + 606555656587.
It is an arithmetic number, because the mean of its divisors is an integer number (606555656587).
Almost surely, 21213111313173 is an apocalyptic number.
It is an amenable number.
1213111313173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213111313173 is an equidigital number, since it uses as much as digits as its factorization.
1213111313173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1134, while the sum is 28.
Adding to 1213111313173 its reverse (3713131113121), we get a palindrome (4926242426294).
The spelling of 1213111313173 in words is "one trillion, two hundred thirteen billion, one hundred eleven million, three hundred thirteen thousand, one hundred seventy-three".
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