Base | Representation |
---|---|
bin | 10110100110001001… |
… | …11100001001100001 |
3 | 1011022110000221020201 |
4 | 23103010330021201 |
5 | 144321043101423 |
6 | 5323434105201 |
7 | 606423454333 |
oct | 132304741141 |
9 | 34273027221 |
10 | 12131222113 |
11 | 51658387aa |
12 | 242687b201 |
13 | 11b43ba64a |
14 | 831219453 |
15 | 4b00412ad |
hex | 2d313c261 |
12131222113 has 2 divisors, whose sum is σ = 12131222114. Its totient is φ = 12131222112.
The previous prime is 12131222111. The next prime is 12131222137. The reversal of 12131222113 is 31122213121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12098240064 + 32982049 = 109992^2 + 5743^2 .
It is a cyclic number.
It is not a de Polignac number, because 12131222113 - 21 = 12131222111 is a prime.
Together with 12131222111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12131222111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065611056 + 6065611057.
It is an arithmetic number, because the mean of its divisors is an integer number (6065611057).
Almost surely, 212131222113 is an apocalyptic number.
It is an amenable number.
12131222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131222113 is an equidigital number, since it uses as much as digits as its factorization.
12131222113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 19.
Adding to 12131222113 its reverse (31122213121), we get a palindrome (43253435234).
The spelling of 12131222113 in words is "twelve billion, one hundred thirty-one million, two hundred twenty-two thousand, one hundred thirteen".
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