Base | Representation |
---|---|
bin | 11011100101010101111011… |
… | …010111010000001101100111 |
3 | 120220112110010220001100021101 |
4 | 123211111323113100031213 |
5 | 111400044341232000212 |
6 | 1110002341034300531 |
7 | 34360414443210514 |
oct | 3345257327201547 |
9 | 526473126040241 |
10 | 121313420968807 |
11 | 35721807558961 |
12 | 1173342b287747 |
13 | 528ca63b99772 |
14 | 21d585ac4630b |
15 | e05991934157 |
hex | 6e557b5d0367 |
121313420968807 has 2 divisors, whose sum is σ = 121313420968808. Its totient is φ = 121313420968806.
The previous prime is 121313420968801. The next prime is 121313420968841. The reversal of 121313420968807 is 708869024313121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121313420968807 - 231 = 121311273485159 is a prime.
It is a super-2 number, since 2×1213134209688072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121313420968801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60656710484403 + 60656710484404.
It is an arithmetic number, because the mean of its divisors is an integer number (60656710484404).
Almost surely, 2121313420968807 is an apocalyptic number.
121313420968807 is a deficient number, since it is larger than the sum of its proper divisors (1).
121313420968807 is an equidigital number, since it uses as much as digits as its factorization.
121313420968807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3483648, while the sum is 55.
The spelling of 121313420968807 in words is "one hundred twenty-one trillion, three hundred thirteen billion, four hundred twenty million, nine hundred sixty-eight thousand, eight hundred seven".
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