Base | Representation |
---|---|
bin | 11011100101011100000100… |
… | …001110000101011100010111 |
3 | 120220120002011020020222210211 |
4 | 123211130010032011130113 |
5 | 111400201341033330122 |
6 | 1110005351043230251 |
7 | 34361036665150015 |
oct | 3345340416053427 |
9 | 526502136228724 |
10 | 121320012011287 |
11 | 35724589a79701 |
12 | 1173476a678387 |
13 | 5290574545bbb |
14 | 21d5cc43498b5 |
15 | e05c2a3ba877 |
hex | 6e5704385717 |
121320012011287 has 2 divisors, whose sum is σ = 121320012011288. Its totient is φ = 121320012011286.
The previous prime is 121320012011257. The next prime is 121320012011291. The reversal of 121320012011287 is 782110210023121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121320012011287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121320012011227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60660006005643 + 60660006005644.
It is an arithmetic number, because the mean of its divisors is an integer number (60660006005644).
Almost surely, 2121320012011287 is an apocalyptic number.
121320012011287 is a deficient number, since it is larger than the sum of its proper divisors (1).
121320012011287 is an equidigital number, since it uses as much as digits as its factorization.
121320012011287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 31.
The spelling of 121320012011287 in words is "one hundred twenty-one trillion, three hundred twenty billion, twelve million, eleven thousand, two hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •