Base | Representation |
---|---|
bin | 1011000010001011100110… |
… | …1001000110000000000011 |
3 | 1120221211002001200020112102 |
4 | 2300202321221012000003 |
5 | 3042233021130420342 |
6 | 41445224422421015 |
7 | 2361341542132532 |
oct | 260427151060003 |
9 | 46854061606472 |
10 | 12132102201347 |
11 | 3958217455a17 |
12 | 143b34859176b |
13 | 6a008ac7322b |
14 | 2dd2a8348319 |
15 | 1608b55d3832 |
hex | b08b9a46003 |
12132102201347 has 2 divisors, whose sum is σ = 12132102201348. Its totient is φ = 12132102201346.
The previous prime is 12132102201287. The next prime is 12132102201379. The reversal of 12132102201347 is 74310220123121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12132102201347 - 224 = 12132085424131 is a prime.
It is a super-2 number, since 2×121321022013472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12132102200347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066051100673 + 6066051100674.
It is an arithmetic number, because the mean of its divisors is an integer number (6066051100674).
Almost surely, 212132102201347 is an apocalyptic number.
12132102201347 is a deficient number, since it is larger than the sum of its proper divisors (1).
12132102201347 is an equidigital number, since it uses as much as digits as its factorization.
12132102201347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 12132102201347 its reverse (74310220123121), we get a palindrome (86442322324468).
The spelling of 12132102201347 in words is "twelve trillion, one hundred thirty-two billion, one hundred two million, two hundred one thousand, three hundred forty-seven".
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