Base | Representation |
---|---|
bin | 1011000010001011101000… |
… | …1011000010100011101101 |
3 | 1120221211002200102100101101 |
4 | 2300202322023002203231 |
5 | 3042233030420201031 |
6 | 41445225341243101 |
7 | 2361342010564534 |
oct | 260427213024355 |
9 | 46854080370341 |
10 | 12132111100141 |
11 | 395822148379a |
12 | 143b34b563491 |
13 | 6a008ca6a7a6 |
14 | 2dd2a95c331b |
15 | 1608b6290361 |
hex | b08ba2c28ed |
12132111100141 has 2 divisors, whose sum is σ = 12132111100142. Its totient is φ = 12132111100140.
The previous prime is 12132111100079. The next prime is 12132111100177. The reversal of 12132111100141 is 14100111123121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10553434446025 + 1578676654116 = 3248605^2 + 1256454^2 .
It is a cyclic number.
It is not a de Polignac number, because 12132111100141 - 27 = 12132111100013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12132115100141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066055550070 + 6066055550071.
It is an arithmetic number, because the mean of its divisors is an integer number (6066055550071).
Almost surely, 212132111100141 is an apocalyptic number.
It is an amenable number.
12132111100141 is a deficient number, since it is larger than the sum of its proper divisors (1).
12132111100141 is an equidigital number, since it uses as much as digits as its factorization.
12132111100141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 12132111100141 its reverse (14100111123121), we get a palindrome (26232222223262).
The spelling of 12132111100141 in words is "twelve trillion, one hundred thirty-two billion, one hundred eleven million, one hundred thousand, one hundred forty-one".
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