Base | Representation |
---|---|
bin | 111000011111101100… |
… | …0000000101111110101 |
3 | 102121011011101121122102 |
4 | 1300333120000233311 |
5 | 3441432004442123 |
6 | 131422410511445 |
7 | 11523323622005 |
oct | 1607730005765 |
9 | 377134347572 |
10 | 121322343413 |
11 | 474a8333317 |
12 | 1b61a735585 |
13 | b5961462ab |
14 | 5c2cc02005 |
15 | 325110b028 |
hex | 1c3f600bf5 |
121322343413 has 2 divisors, whose sum is σ = 121322343414. Its totient is φ = 121322343412.
The previous prime is 121322343403. The next prime is 121322343451. The reversal of 121322343413 is 314343223121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97198662289 + 24123681124 = 311767^2 + 155318^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121322343413 is a prime.
It is a super-2 number, since 2×1213223434132 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121322343403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60661171706 + 60661171707.
It is an arithmetic number, because the mean of its divisors is an integer number (60661171707).
Almost surely, 2121322343413 is an apocalyptic number.
It is an amenable number.
121322343413 is a deficient number, since it is larger than the sum of its proper divisors (1).
121322343413 is an equidigital number, since it uses as much as digits as its factorization.
121322343413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 29.
Adding to 121322343413 its reverse (314343223121), we get a palindrome (435665566534).
The spelling of 121322343413 in words is "one hundred twenty-one billion, three hundred twenty-two million, three hundred forty-three thousand, four hundred thirteen".
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