Base | Representation |
---|---|
bin | 1011000010001100011101… |
… | …1010000001001000111111 |
3 | 1120221211200011012122111201 |
4 | 2300203013122001020333 |
5 | 3042234004240132203 |
6 | 41445303352200331 |
7 | 2361350345035021 |
oct | 260430732011077 |
9 | 46854604178451 |
10 | 12132333130303 |
11 | 39583258432a1 |
12 | 143b3b19990a7 |
13 | 6a00c6a69299 |
14 | 2dd2cac9c011 |
15 | 1608ca9ebe1d |
hex | b08c768123f |
12132333130303 has 2 divisors, whose sum is σ = 12132333130304. Its totient is φ = 12132333130302.
The previous prime is 12132333130283. The next prime is 12132333130321. The reversal of 12132333130303 is 30303133323121.
It is a strong prime.
It is an emirp because it is prime and its reverse (30303133323121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12132333130303 - 213 = 12132333122111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12132333130003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066166565151 + 6066166565152.
It is an arithmetic number, because the mean of its divisors is an integer number (6066166565152).
Almost surely, 212132333130303 is an apocalyptic number.
12132333130303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12132333130303 is an equidigital number, since it uses as much as digits as its factorization.
12132333130303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 28.
Adding to 12132333130303 its reverse (30303133323121), we get a palindrome (42435466453424).
The spelling of 12132333130303 in words is "twelve trillion, one hundred thirty-two billion, three hundred thirty-three million, one hundred thirty thousand, three hundred three".
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