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12132421447 is a prime number
BaseRepresentation
bin10110100110010011…
…00000111101000111
31011022112021212102111
423103021200331013
5144321344441242
65323515521451
7606436611046
oct132311407507
934275255374
1012132421447
115166487893
122427159287
1311b471a503
1483144c55d
154b01cb817
hex2d3260f47

12132421447 has 2 divisors, whose sum is σ = 12132421448. Its totient is φ = 12132421446.

The previous prime is 12132421351. The next prime is 12132421451. The reversal of 12132421447 is 74412423121.

12132421447 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (74412423121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12132421447 - 219 = 12131897159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12132421247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066210723 + 6066210724.

It is an arithmetic number, because the mean of its divisors is an integer number (6066210724).

Almost surely, 212132421447 is an apocalyptic number.

12132421447 is a deficient number, since it is larger than the sum of its proper divisors (1).

12132421447 is an equidigital number, since it uses as much as digits as its factorization.

12132421447 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10752, while the sum is 31.

Adding to 12132421447 its reverse (74412423121), we get a palindrome (86544844568).

The spelling of 12132421447 in words is "twelve billion, one hundred thirty-two million, four hundred twenty-one thousand, four hundred forty-seven".