Base | Representation |
---|---|
bin | 1011000010001100110010… |
… | …1110110010111010010001 |
3 | 1120221211220101022020002121 |
4 | 2300203030232302322101 |
5 | 3042234200122304441 |
6 | 41445320303014241 |
7 | 2361352511251402 |
oct | 260431456627221 |
9 | 46854811266077 |
10 | 12132422463121 |
11 | 3958371209374 |
12 | 143b41789a381 |
13 | 6a010c41663c |
14 | 2dd2d8ab39a9 |
15 | 1608d3795dd1 |
hex | b08ccbb2e91 |
12132422463121 has 2 divisors, whose sum is σ = 12132422463122. Its totient is φ = 12132422463120.
The previous prime is 12132422463107. The next prime is 12132422463163. The reversal of 12132422463121 is 12136422423121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12085628120721 + 46794342400 = 3476439^2 + 216320^2 .
It is a cyclic number.
It is not a de Polignac number, because 12132422463121 - 25 = 12132422463089 is a prime.
It is not a weakly prime, because it can be changed into another prime (12132422461121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066211231560 + 6066211231561.
It is an arithmetic number, because the mean of its divisors is an integer number (6066211231561).
Almost surely, 212132422463121 is an apocalyptic number.
It is an amenable number.
12132422463121 is a deficient number, since it is larger than the sum of its proper divisors (1).
12132422463121 is an equidigital number, since it uses as much as digits as its factorization.
12132422463121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 27648, while the sum is 34.
Adding to 12132422463121 its reverse (12136422423121), we get a palindrome (24268844886242).
The spelling of 12132422463121 in words is "twelve trillion, one hundred thirty-two billion, four hundred twenty-two million, four hundred sixty-three thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •