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12132441103 is a prime number
BaseRepresentation
bin10110100110010011…
…00101110000001111
31011022112022212101111
423103021211300033
5144321401103403
65323520152451
7606440022256
oct132311456017
934275285344
1012132441103
1151664a0632
122427168727
1311b4726443
1483145579d
154b01d256d
hex2d3265c0f

12132441103 has 2 divisors, whose sum is σ = 12132441104. Its totient is φ = 12132441102.

The previous prime is 12132441067. The next prime is 12132441151. The reversal of 12132441103 is 30114423121.

12132441103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12132441103 - 217 = 12132310031 is a prime.

It is a super-2 number, since 2×121324411032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12132445103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066220551 + 6066220552.

It is an arithmetic number, because the mean of its divisors is an integer number (6066220552).

Almost surely, 212132441103 is an apocalyptic number.

12132441103 is a deficient number, since it is larger than the sum of its proper divisors (1).

12132441103 is an equidigital number, since it uses as much as digits as its factorization.

12132441103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12132441103 its reverse (30114423121), we get a palindrome (42246864224).

The spelling of 12132441103 in words is "twelve billion, one hundred thirty-two million, four hundred forty-one thousand, one hundred three".