Base | Representation |
---|---|
bin | 111000011111110001… |
… | …0100010010000110110 |
3 | 102121011100120202220021 |
4 | 1300333202202100312 |
5 | 3441433211232014 |
6 | 131422545555354 |
7 | 11523356231635 |
oct | 1607742422066 |
9 | 377140522807 |
10 | 121325102134 |
11 | 474a9947a55 |
12 | 1b61b645b5a |
13 | b5968a0b82 |
14 | 5c2d31d51c |
15 | 32514a3624 |
hex | 1c3f8a2436 |
121325102134 has 4 divisors (see below), whose sum is σ = 181987653204. Its totient is φ = 60662551066.
The previous prime is 121325102089. The next prime is 121325102141. The reversal of 121325102134 is 431201523121.
121325102134 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 121325102099 and 121325102108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30331275532 + ... + 30331275535.
It is an arithmetic number, because the mean of its divisors is an integer number (45496913301).
Almost surely, 2121325102134 is an apocalyptic number.
121325102134 is a deficient number, since it is larger than the sum of its proper divisors (60662551070).
121325102134 is an equidigital number, since it uses as much as digits as its factorization.
121325102134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60662551069.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 121325102134 its reverse (431201523121), we get a palindrome (552526625255).
The spelling of 121325102134 in words is "one hundred twenty-one billion, three hundred twenty-five million, one hundred two thousand, one hundred thirty-four".
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