Base | Representation |
---|---|
bin | 1011000010001110111100… |
… | …1010000011010000101111 |
3 | 1120221220101122002211110201 |
4 | 2300203233022003100233 |
5 | 3042241341002031302 |
6 | 41445453454214331 |
7 | 2361403023441505 |
oct | 260435712032057 |
9 | 46856348084421 |
10 | 12133000033327 |
11 | 3958638237418 |
12 | 143b5591b43a7 |
13 | 6a01a1c8ab64 |
14 | 2dd35169c675 |
15 | 160919332c87 |
hex | b08ef28342f |
12133000033327 has 2 divisors, whose sum is σ = 12133000033328. Its totient is φ = 12133000033326.
The previous prime is 12133000033201. The next prime is 12133000033361. The reversal of 12133000033327 is 72333000033121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12133000033327 - 219 = 12132999509039 is a prime.
It is a super-2 number, since 2×121330000333272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12133000033295 and 12133000033304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12133000033367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066500016663 + 6066500016664.
It is an arithmetic number, because the mean of its divisors is an integer number (6066500016664).
Almost surely, 212133000033327 is an apocalyptic number.
12133000033327 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133000033327 is an equidigital number, since it uses as much as digits as its factorization.
12133000033327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 28.
Adding to 12133000033327 its reverse (72333000033121), we get a palindrome (84466000066448).
The spelling of 12133000033327 in words is "twelve trillion, one hundred thirty-three billion, thirty-three thousand, three hundred twenty-seven".
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