Base | Representation |
---|---|
bin | 1011000010001111000001… |
… | …0101100110101001010111 |
3 | 1120221220110000101001211111 |
4 | 2300203300111212221113 |
5 | 3042241411034322223 |
6 | 41445455442515451 |
7 | 2361403354001254 |
oct | 260436025465127 |
9 | 46856400331744 |
10 | 12133019839063 |
11 | 39586484347a2 |
12 | 143b563965b87 |
13 | 6a01a6103a26 |
14 | 2dd35417642b |
15 | 16091ae4630d |
hex | b08f0566a57 |
12133019839063 has 2 divisors, whose sum is σ = 12133019839064. Its totient is φ = 12133019839062.
The previous prime is 12133019839043. The next prime is 12133019839081. The reversal of 12133019839063 is 36093891033121.
It is a strong prime.
It is an emirp because it is prime and its reverse (36093891033121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12133019839063 - 213 = 12133019830871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12133019838998 and 12133019839016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12133019839043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066509919531 + 6066509919532.
It is an arithmetic number, because the mean of its divisors is an integer number (6066509919532).
Almost surely, 212133019839063 is an apocalyptic number.
12133019839063 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133019839063 is an equidigital number, since it uses as much as digits as its factorization.
12133019839063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 629856, while the sum is 49.
The spelling of 12133019839063 in words is "twelve trillion, one hundred thirty-three billion, nineteen million, eight hundred thirty-nine thousand, sixty-three".
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