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12133102019981 is a prime number
BaseRepresentation
bin1011000010001111010100…
…1111000110010110001101
31120221220122202000021212012
42300203311033012112031
53042242043104114411
641445511540151005
72361405402346625
oct260436517062615
946856582007765
1012133102019981
11395868a865508
12143b587398465
136a01ba1489a7
142dd361049885
1516092327b18b
hexb08f53c658d

12133102019981 has 2 divisors, whose sum is σ = 12133102019982. Its totient is φ = 12133102019980.

The previous prime is 12133102019939. The next prime is 12133102020007. The reversal of 12133102019981 is 18991020133121.

12133102019981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12094856350756 + 38245669225 = 3477766^2 + 195565^2 .

It is a cyclic number.

It is not a de Polignac number, because 12133102019981 - 226 = 12133034911117 is a prime.

It is a super-2 number, since 2×121331020199812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12133302019981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066551009990 + 6066551009991.

It is an arithmetic number, because the mean of its divisors is an integer number (6066551009991).

Almost surely, 212133102019981 is an apocalyptic number.

It is an amenable number.

12133102019981 is a deficient number, since it is larger than the sum of its proper divisors (1).

12133102019981 is an equidigital number, since it uses as much as digits as its factorization.

12133102019981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 41.

The spelling of 12133102019981 in words is "twelve trillion, one hundred thirty-three billion, one hundred two million, nineteen thousand, nine hundred eighty-one".