Base | Representation |
---|---|
bin | 11011100101100110010101… |
… | …000100001111000010011001 |
3 | 120220121010121020102110210021 |
4 | 123211212111010033002121 |
5 | 111400341423201410212 |
6 | 1110014412345150441 |
7 | 34361610040054051 |
oct | 3345462504170231 |
9 | 526533536373707 |
10 | 121331032060057 |
11 | 35729224560426 |
12 | 1173692518b421 |
13 | 529160c66cc11 |
14 | 21d664bb58561 |
15 | e06172aba307 |
hex | 6e599510f099 |
121331032060057 has 2 divisors, whose sum is σ = 121331032060058. Its totient is φ = 121331032060056.
The previous prime is 121331032059949. The next prime is 121331032060061. The reversal of 121331032060057 is 750060230133121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72348446512521 + 48982585547536 = 8505789^2 + 6998756^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121331032060057 is a prime.
It is not a weakly prime, because it can be changed into another prime (121331032060087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60665516030028 + 60665516030029.
It is an arithmetic number, because the mean of its divisors is an integer number (60665516030029).
Almost surely, 2121331032060057 is an apocalyptic number.
It is an amenable number.
121331032060057 is a deficient number, since it is larger than the sum of its proper divisors (1).
121331032060057 is an equidigital number, since it uses as much as digits as its factorization.
121331032060057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 34.
Adding to 121331032060057 its reverse (750060230133121), we get a palindrome (871391262193178).
The spelling of 121331032060057 in words is "one hundred twenty-one trillion, three hundred thirty-one billion, thirty-two million, sixty thousand, fifty-seven".
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