Base | Representation |
---|---|
bin | 11011100101100110011001… |
… | …010111100011101100011111 |
3 | 120220121010210021020022012022 |
4 | 123211212121113203230133 |
5 | 111400342100140444041 |
6 | 1110014423444130355 |
7 | 34361611604404361 |
oct | 3345463127435437 |
9 | 526533707208168 |
10 | 121331104234271 |
11 | 35729261276a38 |
12 | 117369453969bb |
13 | 52916215c0259 |
14 | 21d6657584d31 |
15 | e061790c524b |
hex | 6e59995e3b1f |
121331104234271 has 2 divisors, whose sum is σ = 121331104234272. Its totient is φ = 121331104234270.
The previous prime is 121331104234267. The next prime is 121331104234391. The reversal of 121331104234271 is 172432401133121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121331104234271 - 22 = 121331104234267 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121331104224271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60665552117135 + 60665552117136.
It is an arithmetic number, because the mean of its divisors is an integer number (60665552117136).
Almost surely, 2121331104234271 is an apocalyptic number.
121331104234271 is a deficient number, since it is larger than the sum of its proper divisors (1).
121331104234271 is an equidigital number, since it uses as much as digits as its factorization.
121331104234271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 121331104234271 its reverse (172432401133121), we get a palindrome (293763505367392).
The spelling of 121331104234271 in words is "one hundred twenty-one trillion, three hundred thirty-one billion, one hundred four million, two hundred thirty-four thousand, two hundred seventy-one".
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