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12133113300 = 223252711175081
BaseRepresentation
bin10110100110011000…
…01001110111010100
31011022120121000110200
423103030021313110
5144322034111200
65323542420500
7606445522110
oct132314116724
934276530420
1012133113300
11516690a670
122427431730
1311b49003a9
1483158c740
154b02b6800
hex2d3309dd4

12133113300 has 216 divisors, whose sum is σ = 47415006912. Its totient is φ = 2521152000.

The previous prime is 12133113257. The next prime is 12133113323. The reversal of 12133113300 is 331133121.

It is a happy number.

12133113300 is a `hidden beast` number, since 1 + 2 + 1 + 331 + 1 + 330 + 0 = 666.

12133113300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 18241 + ... + 156840.

Almost surely, 212133113300 is an apocalyptic number.

12133113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12133113300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23707503456).

12133113300 is an abundant number, since it is smaller than the sum of its proper divisors (35281893612).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12133113300 is a wasteful number, since it uses less digits than its factorization.

12133113300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175119 (or 175109 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 12133113300 its reverse (331133121), we get a palindrome (12464246421).

The spelling of 12133113300 in words is "twelve billion, one hundred thirty-three million, one hundred thirteen thousand, three hundred".