Base | Representation |
---|---|
bin | 1011000010010000000110… |
… | …1001101010011010110011 |
3 | 1120221221012020221112010211 |
4 | 2300210001221222122303 |
5 | 3042243004414410232 |
6 | 41445544340404551 |
7 | 2361413511652432 |
oct | 260440151523263 |
9 | 46857166845124 |
10 | 12133310310067 |
11 | 395878739a981 |
12 | 143b6250a6757 |
13 | 6a022134646b |
14 | 2dd380989119 |
15 | 1609366c1a47 |
hex | b0901a6a6b3 |
12133310310067 has 2 divisors, whose sum is σ = 12133310310068. Its totient is φ = 12133310310066.
The previous prime is 12133310310059. The next prime is 12133310310089. The reversal of 12133310310067 is 76001301333121.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (76001301333121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12133310310067 - 23 = 12133310310059 is a prime.
It is not a weakly prime, because it can be changed into another prime (12133310310767) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066655155033 + 6066655155034.
It is an arithmetic number, because the mean of its divisors is an integer number (6066655155034).
Almost surely, 212133310310067 is an apocalyptic number.
12133310310067 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133310310067 is an equidigital number, since it uses as much as digits as its factorization.
12133310310067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 12133310310067 its reverse (76001301333121), we get a palindrome (88134611643188).
The spelling of 12133310310067 in words is "twelve trillion, one hundred thirty-three billion, three hundred ten million, three hundred ten thousand, sixty-seven".
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