Base | Representation |
---|---|
bin | 1011000010010000001001… |
… | …0111100001101110110011 |
3 | 1120221221020002120100122121 |
4 | 2300210002113201232303 |
5 | 3042243021004124412 |
6 | 41445545450215111 |
7 | 2361414016106143 |
oct | 260440227415663 |
9 | 46857202510577 |
10 | 12133322333107 |
11 | 3958793161a78 |
12 | 143b629124497 |
13 | 6a0223995aa1 |
14 | 2dd3823d8923 |
15 | 160937799107 |
hex | b09025e1bb3 |
12133322333107 has 2 divisors, whose sum is σ = 12133322333108. Its totient is φ = 12133322333106.
The previous prime is 12133322333017. The next prime is 12133322333123. The reversal of 12133322333107 is 70133322333121.
Together with previous prime (12133322333017) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12133322333107 - 215 = 12133322300339 is a prime.
It is a super-3 number, since 3×121333223331073 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12133322337107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066661166553 + 6066661166554.
It is an arithmetic number, because the mean of its divisors is an integer number (6066661166554).
Almost surely, 212133322333107 is an apocalyptic number.
12133322333107 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133322333107 is an equidigital number, since it uses as much as digits as its factorization.
12133322333107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 34.
Adding to 12133322333107 its reverse (70133322333121), we get a palindrome (82266644666228).
The spelling of 12133322333107 in words is "twelve trillion, one hundred thirty-three billion, three hundred twenty-two million, three hundred thirty-three thousand, one hundred seven".
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