Base | Representation |
---|---|
bin | 111000100000000010… |
… | …0111110101001001101 |
3 | 102121011222120111112222 |
4 | 1301000010332221031 |
5 | 3441443014200102 |
6 | 131423511305125 |
7 | 11523526045652 |
oct | 1610004765115 |
9 | 377158514488 |
10 | 121334131277 |
11 | 47503a54757 |
12 | 1b62267b1a5 |
13 | b598712868 |
14 | 5c305cdc29 |
15 | 3252188aa2 |
hex | 1c4013ea4d |
121334131277 has 2 divisors, whose sum is σ = 121334131278. Its totient is φ = 121334131276.
The previous prime is 121334131273. The next prime is 121334131283. The reversal of 121334131277 is 772131433121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 62373064516 + 58961066761 = 249746^2 + 242819^2 .
It is an emirp because it is prime and its reverse (772131433121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121334131277 - 22 = 121334131273 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121334131273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60667065638 + 60667065639.
It is an arithmetic number, because the mean of its divisors is an integer number (60667065639).
Almost surely, 2121334131277 is an apocalyptic number.
It is an amenable number.
121334131277 is a deficient number, since it is larger than the sum of its proper divisors (1).
121334131277 is an equidigital number, since it uses as much as digits as its factorization.
121334131277 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21168, while the sum is 35.
Adding to 121334131277 its reverse (772131433121), we get a palindrome (893465564398).
The spelling of 121334131277 in words is "one hundred twenty-one billion, three hundred thirty-four million, one hundred thirty-one thousand, two hundred seventy-seven".
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