121340414113 has 2 divisors, whose sum is σ = 121340414114. Its totient is φ = 121340414112.

The previous prime is 121340414099. The next prime is 121340414141. The reversal of 121340414113 is 311414043121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60965535744 + 60374878369 = 246912^2 + 245713^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121340414113 is a prime.

It is a super-2 number, since 2×121340414113² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121340454113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60670207056 + 60670207057.

It is an arithmetic number, because the mean of its divisors is an integer number (60670207057).

Almost surely, 2^121340414113 is an apocalyptic number.

It is an amenable number.

121340414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121340414113 is an equidigital number, since it uses as much as digits as its factorization.

121340414113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 121340414113 its reverse (311414043121), we get a palindrome (432754457234).

The spelling of 121340414113 in words is "one hundred twenty-one billion, three hundred forty million, four hundred fourteen thousand, one hundred thirteen".