Base | Representation |
---|---|
bin | 10110100110011111… |
… | …11101001101010001 |
3 | 1011022122110122201201 |
4 | 23103033331031101 |
5 | 144322313010113 |
6 | 5324020031201 |
7 | 606460143043 |
oct | 132317751521 |
9 | 34278418651 |
10 | 12134110033 |
11 | 5167430511 |
12 | 2427832501 |
13 | 11b4b8bc86 |
14 | 83176ba93 |
15 | 4b0411cdd |
hex | 2d33fd351 |
12134110033 has 2 divisors, whose sum is σ = 12134110034. Its totient is φ = 12134110032.
The previous prime is 12134110031. The next prime is 12134110061. The reversal of 12134110033 is 33001143121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11428251409 + 705858624 = 106903^2 + 26568^2 .
It is a cyclic number.
It is not a de Polignac number, because 12134110033 - 21 = 12134110031 is a prime.
It is a super-2 number, since 2×121341100332 (a number of 21 digits) contains 22 as substring.
Together with 12134110031, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12134110031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067055016 + 6067055017.
It is an arithmetic number, because the mean of its divisors is an integer number (6067055017).
Almost surely, 212134110033 is an apocalyptic number.
It is an amenable number.
12134110033 is a deficient number, since it is larger than the sum of its proper divisors (1).
12134110033 is an equidigital number, since it uses as much as digits as its factorization.
12134110033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12134110033 its reverse (33001143121), we get a palindrome (45135253154).
The spelling of 12134110033 in words is "twelve billion, one hundred thirty-four million, one hundred ten thousand, thirty-three".
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