Base | Representation |
---|---|
bin | 111000100000001111… |
… | …1111110111100110111 |
3 | 102121012110220011022120 |
4 | 1301000133332330313 |
5 | 3442001322213143 |
6 | 131424323131023 |
7 | 11523643161606 |
oct | 1610037767467 |
9 | 377173804276 |
10 | 121341210423 |
11 | 47507a4a394 |
12 | 1b624b13a73 |
13 | b59a020ac4 |
14 | 5c31513a3d |
15 | 3252ad6383 |
hex | 1c407fef37 |
121341210423 has 32 divisors (see below), whose sum is σ = 170635548672. Its totient is φ = 76547328000.
The previous prime is 121341210421. The next prime is 121341210457. The reversal of 121341210423 is 324012143121.
It is not a de Polignac number, because 121341210423 - 21 = 121341210421 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121341210393 and 121341210402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121341210421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9241303 + ... + 9254423.
It is an arithmetic number, because the mean of its divisors is an integer number (5332360896).
Almost surely, 2121341210423 is an apocalyptic number.
121341210423 is a deficient number, since it is larger than the sum of its proper divisors (49294338249).
121341210423 is a wasteful number, since it uses less digits than its factorization.
121341210423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14575.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 121341210423 its reverse (324012143121), we get a palindrome (445353353544).
The spelling of 121341210423 in words is "one hundred twenty-one billion, three hundred forty-one million, two hundred ten thousand, four hundred twenty-three".
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