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12134130023 is a prime number
BaseRepresentation
bin10110100110100000…
…00010000101100111
31011022122111200011002
423103100002011213
5144322314130043
65324020303515
7606460255241
oct132320020547
934278450132
1012134130023
115167444534
122427841b9b
1311b4b980c2
14831775091
154b0417bb8
hex2d3402167

12134130023 has 2 divisors, whose sum is σ = 12134130024. Its totient is φ = 12134130022.

The previous prime is 12134130011. The next prime is 12134130049. The reversal of 12134130023 is 32003143121.

It is a weak prime.

It is an emirp because it is prime and its reverse (32003143121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12134130023 - 228 = 11865694567 is a prime.

It is a super-2 number, since 2×121341300232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12134129977 and 12134130004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12134130083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067065011 + 6067065012.

It is an arithmetic number, because the mean of its divisors is an integer number (6067065012).

Almost surely, 212134130023 is an apocalyptic number.

12134130023 is a deficient number, since it is larger than the sum of its proper divisors (1).

12134130023 is an equidigital number, since it uses as much as digits as its factorization.

12134130023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 12134130023 its reverse (32003143121), we get a palindrome (44137273144).

The spelling of 12134130023 in words is "twelve billion, one hundred thirty-four million, one hundred thirty thousand, twenty-three".