Base | Representation |
---|---|
bin | 11011100101110000100100… |
… | …001011101111001001111110 |
3 | 120220122011222020000022101121 |
4 | 123211300210023233021332 |
5 | 111401031430403244402 |
6 | 1110023431133301154 |
7 | 34362446310303244 |
oct | 3345604413571176 |
9 | 526564866008347 |
10 | 121342023103102 |
11 | 3573295473077a |
12 | 11738a920347ba |
13 | 529267177c699 |
14 | 21d6db1776794 |
15 | e065b798a837 |
hex | 6e5c242ef27e |
121342023103102 has 4 divisors (see below), whose sum is σ = 182013034654656. Its totient is φ = 60671011551550.
The previous prime is 121342023103097. The next prime is 121342023103111. The reversal of 121342023103102 is 201301320243121.
It is a semiprime because it is the product of two primes.
It is a super-4 number, since 4×1213420231031024 (a number of 57 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30335505775774 + ... + 30335505775777.
It is an arithmetic number, because the mean of its divisors is an integer number (45503258663664).
Almost surely, 2121342023103102 is an apocalyptic number.
121342023103102 is a deficient number, since it is larger than the sum of its proper divisors (60671011551554).
121342023103102 is an equidigital number, since it uses as much as digits as its factorization.
121342023103102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60671011551553.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 121342023103102 its reverse (201301320243121), we get a palindrome (322643343346223).
The spelling of 121342023103102 in words is "one hundred twenty-one trillion, three hundred forty-two billion, twenty-three million, one hundred three thousand, one hundred two".
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